JEE MATHEMATICS MCQ: ELLIPSE

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The locus of the point of intersection of perpendicular tangents to the ellipse

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

View answer and explanation

Correct option: C

x^2+y^2=a^2+b^2

Option C (

x^2+y^2=a^2+b^2

) is correct because the locus of the point of intersection of perpendicular tangents to an ellipse is its director circle, which has the equation

x^2 + y^2 = a^2 + b^2

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