If $\tan ({A}+{B})=3 \tan {A}$, then $\frac{\sin 2({A}+{B})+\sin 2 {A}}{\sin 2 {B}}=$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

\tan ({A}+{B})=3 \tan {A}

, then

\frac{\sin 2({A}+{B})+\sin 2 {A}}{\sin 2 {B}}=

View answer and explanation

Correct option: A

Option A (2) is correct because it represents the value of the expression

\frac{{\sin 2(A+B)+\sin 2 A}}{{\sin 2 B}}

given the condition

\tan (A+B)=3 \tan A

, which simplifies to 2 using trigonometric identities.

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