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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
For x∈R,x≠0x \in R, x \neq 0, if y(x)y(x) is differentiable function such that x∫1xy(t)dt=(x+1)∫1xty(t)dtx \int_1^x y(t) d t=(x+1) \int_1^x t y(t) d t, then y(x)y(x) equals (where CC is a constant).
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Correct option: D
Cx3e−1/x\frac{C}{x^3} e^{-1 / x}
Option D (Cx3e−1/x\frac{C}{x^3} e^{-1 / x}) is correct because it is the solution to the differential equation obtained after differentiating the given integral equation twice.

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