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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(−7x+24y)JU = \left( { - 7x + 24y} \right)J, x and y being in metre. If the particle starts from rest from origin then speed of particle at t=2 s is
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Correct option: D
10 ms−110\,m{s^{ - 1}}
Option D is correct because the force is derived from the potential energy gradient, and then Newton's second law is used to find the acceleration, which is then used to calculate the final speed.

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