JEE PHYSICS MCQ: WAVES

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Application +4 | -1

If

{L_1}

and

{L_2}

are the lengths of the first and second resonating air columns in a resonance tube, then the wavelength of the note produced is

View answer and explanation

Correct option: B

2\left( {{L_2} - {L_1}} \right)

Option B (

2\left( {{L_2} - {L_1}} \right)

) is correct because the wavelength is twice the difference between the second and first resonating lengths in a resonance tube experiment.

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The source of sound generating a frequency of

3\,\,kHz

reaches an observer with a speed of

0.5

times, the velocity of sound in air. The frequency heard by the observer is A source of sound emits waves with frequency

f\mathrm{ }Hz

V\mathrm{ }m/sec

. Two observers move away from this source in opposite directions each with a speed

0.2\,\,V

relative to the source. The ratio of frequencies heard by the two observers will be Assertion: The wave function of a pulse is given by

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

it propagates in

(– \mathrm{ve}) \,x

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Reason: The given wave function is of the form

y = f(kx +\omega t),

which represent a wave travelling in negative

X

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0.01\,\,s

. the fundamental frequency is A rope

5 \mathrm{~m}

long has a total mass of

245 \mathrm{~g}

. It is stretched with a constant tension of

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T

is the reverberation time of an auditorium of volume

V