A minimum value of $\mathop \smallint \nolimits_0^x t{e^{{t^2}}}dt$ is

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

A minimum value of

\int \nolimits_0^x t{e^{{t^2}}}dt

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Correct option: A

Option A (0) is correct because the minimum value of the integral is found by finding the critical points and checking the second derivative.

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