The value of $x+y+z$ is 15 if $a, x, y, z, b$ are in A.P. while the value of $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}$ is $\frac{5}{3}$ if $a, x, y, z, b$ are in H.P. Then the value of a and $b$ are

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The value of

x+y+z

is 15 if

a, x, y, z, b

are in A.P. while the value of

\frac{1}{x}+\frac{1}{y}+\frac{1}{z}

\frac{5}{3}

a, x, y, z, b

are in H.P. Then the value of a and

b

are

View answer and explanation

Correct option: B

1 and 9

Option B (1 and 9) is correct because it satisfies both the arithmetic and harmonic progression conditions given in the problem.

Practice All Chapter MCQs →

A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}