Question

The melting point of ${\rm{RbBr}}$ is ${\rm{682}}^\circ {\rm{C}}$, while that of ${\rm{NaF}}$ is ${\rm{988}}^\circ {\rm{C}}$. The principle reason that melting point of ${\rm{NaF}}$ is much higher than that of ${\rm{RbBr}}$ is that :

Accepted Answer

The internuclear distance ${r_{\rm{c}}} + {r_{\rm{a}}}$ is greater for ${\rm{RbBr}}$ than for ${\rm{NaF}}$

Answer

The two crystals are not isomorphous

Answer

The molar mass of ${\rm{NaF}}$ is smaller than that of ${\rm{RbBr}}$

Answer

The bond is ${\rm{RbBr}}$ has more covalent character than the bond in ${\rm{NaF}}$.

NEET UG CHEMISTRY MCQ: SOLID STATE

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