Skip to main content
Back to COMPLEX NUMBERS

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
1 of 1
Application +4 | -1
If α,  β\alpha ,\;\beta be the roots of the quadratic equation x2+x+1=0{x^2} + x + 1 = 0, then the equation whose roots are α19,  β7{\alpha ^{19}},\;{\beta ^7} is
View answer and explanation
Correct option: D
x2+x+1=0{x^2} + x + 1 = 0
Option D (x2+x+1=0{x^2} + x + 1 = 0) is correct because the roots of the new equation are α19{\alpha ^{19}} and β7{\beta ^7}, which simplify to ω\omega and ω2{\omega ^2}, respectively, leading to the original equation.

More Questions from COMPLEX NUMBERS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.