If $a_n=\frac{-2}{4 n^2-16 n+5}$, then $a_1+a_2+\ldots .+a_{25}$ is equal to

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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a_n=\frac{-2}{4 n^2-16 n+5}

, then

a_1+a_2+\ldots .+a_{25}

is equal to

View answer and explanation

Correct option: D

\frac{50}{141}

Option D (

\frac{{50}}{{141}}

) is correct because the sum telescopes, leaving only the first and last terms, which simplify to the given fraction.

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