The order of bond order of $C_2^{2 - },\,N_2^{2 - },O_2^{2 - }$ is

$C_2^{2 - } < O_2^{2 - } < N_2^{2 - }$

$N_2^{2 - } > O_2^{2 - } > C_2^{2 - }$

NEET UG CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Application +4 | -1

The order of bond order of

C_2^{2 - },\,N_2^{2 - },O_2^{2 - }

View answer and explanation

Correct option: A

C_2^{2 - } > \,N_2^{2 - } > O_2^{2 - }

Option A (

C_2^{2 - } > \,N_2^{2 - } > O_2^{2 - }

) is correct because bond order is inversely proportional to the number of antibonding electrons.