If $f\left( 5 \right) = 7$ and $f'\left( 5 \right) = 7$, then $\mathop {\lim }\limits_{x \to 5} \frac{{xf\left( 5 \right) - 5f\left( x \right)}}{{x - 5}}$ is given by

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

f\left( 5 \right) = 7

and

f'\left( 5 \right) = 7

, then

\lim\limits_{x \to 5} \frac{{xf\left( 5 \right) - 5f\left( x \right)}}{{x - 5}}

is given by

View answer and explanation

Correct option: D

- 28

Option D (-28) is correct because by applying L'Hopital's rule, the limit can be evaluated to -28.

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