JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

\lim _{x \rightarrow 0} \frac{\log (\sin 7 x+\cos 7 x)}{\sin 3 x}

equals :

View answer and explanation

Correct option: B

\frac{7}{3}

Option B (

\frac{7}{3}

) is correct because by using L'Hopital's rule and trigonometric identities, the limit evaluates to 7/3.

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\lim \limits_{{x \rightarrow \infty}} x\left(e^{1 / x}-1\right)

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\lim\limits_{n \to \infty } {\left( {1 + \sin \frac{a}{n}} \right)^n}