JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Easy

1 of 1

Analyzing +4 | -1

The function

f

defined by

f\left( x \right) = 4{x^4} - 2x + 1

in increasing for

View answer and explanation

Correct option: D

x > \frac{1}{2}

Option D (

x > \frac{1}{2}

) is correct because the function

f(x) = 4x^4 - 2x + 1

is increasing when its derivative

f'(x) = 16x^3 - 2

is positive, which occurs for

x > \frac{1}{2}

More Questions from INCREASING & DECREASING

Practice All Chapter MCQs →

f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)