JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

I=\int\limits_{0}^{100 \pi} \sqrt{(1-\cos 2 x)} d x

, then the value of

I

View answer and explanation

Correct option: B

200 \sqrt{2}

Option B (

200\sqrt{2}

) is correct because the integral evaluates to

200\sqrt{2}

after using the periodicity of the integrand.

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