JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

If the sum of

n

terms of an AP is

3 n^2+5 n

, then which of its terms is 164 ?

View answer and explanation

Correct option: B

27 th

Option B (27 th) is correct because it is the term number that has a value of 164 in the given arithmetic progression.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

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{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

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\log \left(\frac{a}{3 b}\right)

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G P

a, b, c

\frac{3}{4}