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JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1
A bullet of mass 5 g,5\,g, travelling with a speed of 210  m/s, 210\,\,m/s,\, strikes a fixed wooden target. One-half of its kinetic
energy is converted into heat in the bullet while the other half is converted into heat in the wood. The rise of
temperature of the bullet, if the specific heat of its material is 0.030   calg−1  ∘C−10.030\,\,\,\mathrm{cal }{g^{ - 1}}\,\,^\circ {C^{ - 1}} is close to
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Correct option: A
87.5o C{87.5^\mathrm{o}}\,C
Option A (87.5o C{87.5^\mathrm{o}}\,C) is correct because it is the temperature rise calculated from the heat generated in the bullet, which is half of the kinetic energy converted.

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