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JEE CHEMISTRY MCQ: BIOMOLECULES

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Application +4 | -1

The maximum concentration of zwitter ion of given amino acid will be at

\mathop {N{H_3}}\limits_{\left( {{\text{pKa}} = 9.8} \right)}^ \oplus - C{H_2} - \mathop {C{O_2}H}\limits_{\left( {{\text{pK }}{{\text{a}}_{\text{1}}} = 2.3} \right)}

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Correct option: C

6 (app.)

The correct answer is C (Increases by factor of four) because the rate is proportional to the square of the carbon monoxide concentration.

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(E) Tyrosine

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