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JEE MATHEMATICS MCQ: COMBINATIONS

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Analyzing +4 | -1
The sum ∑r=110(r2+1)×(r!)\sum_{r=1}^{10}\left(r^{2}+1\right) \times(r !) is equal to :
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Correct option: B
10×(1110 \times(11 !)
The correct answer is B (10 ×(11 !)) because the sum telescopes to 10 × 11! after simplification and summation.

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