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JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Application +4 | -1
HOOC−CH2−CH2−COOC2H5→1 equivalentBH3/THFA. HOOC - C{H_2} - C{H_2} - COO{C_2}{H_5}\xrightarrow[{1 \text{ equivalent}}]{{B{H_3}/THF}}A.{\text{ }}

A will be
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Correct option: A
CH2∣CH2OH−CH2−COOC2H5\mathop {C{H_2}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {C{H_2}OH} \end{array}} - C{H_2} - COO{C_2}{H_5}
Option A is correct because BH3BH_3 reduces the carboxylic acid group to an alcohol, while the ester group remains unaffected.

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