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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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\lim \limits_\limits{n \rightarrow \infty}\left(\frac{n}{n^2+1^2}+\frac{n}{n^2+2^2}+\frac{n}{n^2+3^2}+\ldots .+\frac{1}{5 n}\right)\lim \limits_\limits{n \rightarrow \infty}\left(\frac{n}{n^2+1^2}+\frac{n}{n^2+2^2}+\frac{n}{n^2+3^2}+\ldots .+\frac{1}{5 n}\right) is equal to:
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Correct option: D
tan⁡−1(2)\tan ^{-1}(2)
Option D (tan⁡−1(2)\tan^{-1}(2)) is correct because the given limit can be expressed as a Riemann sum, which then converts into a definite integral that evaluates to tan⁡−1(2)\tan^{-1}(2).

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