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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
If y=a11−log⁡axy=a^{\frac{1}{1-\log _a x}} and z=a11−log⁡ay,z=a^{\frac{1}{1-\log _a y}}, then xx is equal to
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Correct option: C
a11−log⁡aza^{\frac{1}{1-\log _a z}}
Option C (a11−log⁡aza^{\frac{1}{1-\log _a z}}) is correct because by substituting and simplifying the given logarithmic equations, we can express x in terms of a and z.

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