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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Let f(x)f(x) be a continuous function such that the area bounded by the curve y=f(x)y=f(x), the xx-axis, and the lines x=0x=0 and x=ax=a is 1+a22sin⁡a.1+\frac{a^2}{2} \sin a. Then,
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Correct option: C
f(a)=asin⁡a+12a2cos⁡af(a)=a \sin a+\frac{1}{2} a^2 \cos a
Option C (f(a)=asin⁡a+12a2cos⁡af(a)=a \sin a+\frac{1}{2} a^2 \cos a) is correct because it is obtained by differentiating the given integral equation using the Fundamental Theorem of Calculus and the product rule.

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