Question

A uniform cylinder of steel of mass ${M}$, radius ${R}$ is palced on frictionless bearings and set to rotate about vertical axis with angular velocity $\omega_0$. After the cylinder has reached the specified state of rotation it is heated without any mechanical contact from temperature $T_0$ to $T_0+\Delta T$. If $\frac{\Delta I}{I}$ is the fractional change in moment of inertia of the cylinder and $\frac{\Delta \omega}{\omega_0}$ be the fractional change in the angular velocity of the cylinder and $\alpha$ be the coefficient of linear expansion, then

Accepted Answer

All of the above

Answer

$\frac{\Delta {I}}{{I}}=\frac{2 \Delta {R}}{{R}}$

Answer

$\frac{\Delta {I}}{{I}}=-\frac{\Delta \omega}{\omega_0}$

Answer

$\frac{\Delta \omega}{\omega_0}=-2 \alpha \Delta {T}$

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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