JEE PHYSICS MCQ: GRAVITATION

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A spherical uniform planet is rotating about its axis. The velocity of a point on its equator is

V.

Due to the rotation of the planet about its axis the acceleration due to gravity

{g}

at equator is 1/2 of

g

at poles. The escape velocity of a particle on the planet in terms of

{V}

from the pole of the planet is

View answer and explanation

Correct option: A

{V_e}=2{V}

Option A (

{V_e}=2{V}

) is correct because by relating the acceleration due to gravity at the equator and poles with the planet's rotation, we can derive the escape velocity in terms of the equatorial velocity V.

More Questions from GRAVITATION

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The escape velocity for a body projected vertically upwards from the surface of the earth is

11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

{45^0}

with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

v_e

. If the body is projected at an angle

\theta

to the horizontal surface of earth, then the escape velocity would be If different planets have the same density but different radii, then the acceleration due to gravity on the surface of the planet is related to the radius (R) of the planet as Which of the following statement is absolutely correct about mass Statement I: An astronaut in a satellite feels weightlessness:

Statement II: As observed by another astronaut's in the same satellite, force of gravity and centrifugal force balance each other. An iron ball and a wooden ball of the same radius are released from a height 'h' in vacuum. The time taken by both of them to reach the ground is