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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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For which of the following, the radius will be same as for hydrogen atom having n=1?

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Correct option: C

\mathrm{B}{\mathrm{e}^{3 + }},n = 2

The correct answer is

\mathrm{B}{\mathrm{e}^{3 + }},n = 2

because the radius of a hydrogen-like atom is proportional to n²/Z, and for Be³⁺ with n=2, the radius is the same as hydrogen with n=1.

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