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JEE MATHEMATICS MCQ: RATE MEASURE

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For a particle moving in a straight line, if time tt be regarded as a function of velocity vv, then the rate of change of the acceleration a is given by
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Correct option: C
−a3d2tdv2- {a^3}\frac{{{d^2}t}}{{d{v^2}}}
Option C (−a3d2tdv2- {a^3}\frac{{{d^2}t}}{{d{v^2}}}) is correct because it represents the rate of change of acceleration with respect to time, derived by treating time as a function of velocity.

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