Skip to main content
Back to PARABOLA

JEE MATHEMATICS MCQ: PARABOLA

1 Medium
1 of 1
Application +4 | -1
The equation of the common tangent to the hyperbola 3x2−y2=33{x^2} - {y^2} = 3 and to the parabola y2=8x{y^2} = 8x is
View answer and explanation
Correct option: D
2x+y+1=02x + y + 1 = 0
Option D (2x+y+1=02x + y + 1 = 0) is correct because it represents a common tangent to both the hyperbola and the parabola.

More Questions from PARABOLA

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.