JEE MATHEMATICS MCQ: BINOMIAL THEOREM

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Analyzing +4 | -1

The coefficient of

{x^n}

in the polynomial

\left( {x + {\;^n}{C_0}} \right)\left( {x + \;3{\;^n}{C_1}} \right)\left( {x + \;5{\;^n}{C_2}} \right) \ldots \left[ {x + \left( {2n + 1} \right){\;^n}{C_n}} \right]

View answer and explanation

Correct option: C

\left( {n + 1} \right){2^n}

The correct answer is C ((

n + 1

)

2^n

) because the coefficient of x^n is the sum of the roots of the polynomial, which can be simplified using binomial properties.

More Questions from BINOMIAL THEOREM

Practice All Chapter MCQs →

\left({ }^{10} C_0\right)^2-\left({ }^{10} C_1\right)^2+\ldots-\left({ }^{10} C_9\right)^2+\left({ }^{10} C_{10}\right)^2

a

d

\left( {n + 1} \right)

a{C_0} - \left( {a + d} \right){C_1} + \left( {a + 2d} \right){C_2} - ... + ...

(1-x)^{201}\left(1+x+x^2\right)^{200}

\left(\frac{1}{x}+2 x\right)^n

{x^5}

\frac{{1 + {x^2}}}{{1 + x}},\left| x \right| < 1,

\left(\begin{array}{c}2 n+1 \\ 0\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 3\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 6\end{array}\right)+\ldots=170

n