JEE PHYSICS MCQ: RAY OPTICS

1 Hard

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Application +4 | -1

A ray enters a glass slab at an angle

\alpha

from air and the refractive index varies along the slab as

\mu=\mu_0-k t^2

where

t

is the distance measured along the normal.

\mu_0

and

k

are positive constants. If the glass slab is sufficiently thick, how far along the normal will the ray go before it reflects back?

View answer and explanation

Correct option: C

\sqrt{\frac{\mu_0-\sin \theta}{k}}

Option C (

\sqrt{\frac{\mu_0-\sin \theta}{k}}

) is correct because the distance is found by setting the refractive index at the reflection point equal to the sine of the incident angle.

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