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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
How many numbers between 5000 and 10,000 can be formed using the digits 1,2,3,4,5,6,7,8,9, each digit appearing not more than once in each number?
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Correct option: A
5×  8P35 \times {\;^8}{P_3}
Option A (5×  8P35 \times {\;^8}{P_3}) is correct because there are 5 choices for the thousands digit (5, 6, 7, 8, 9) and then 8ˆP3{{\^8}P_3} ways to arrange the remaining 3 digits from the remaining 8 digits.

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