JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

The number of solutions of

\sin \,\,x = \sin \,\,2x

between

\frac{{ - \pi }}{2}

and

\frac{\pi }{2}

View answer and explanation

Correct option: A

The correct answer is A (3) because solving the trigonometric equation

\sin x = \sin 2x

within the given interval yields three solutions: 0,

\frac{\pi}{3}

, and

-\frac{\pi}{3}

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