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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1
The momentum of a photon of wavelength 6626 nm\mathrm{nm} will be
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Correct option: A
10βˆ’28Β kgΒ msβˆ’110^{-28} \mathrm{~kg} \mathrm{~ms}^{-1}
Option A (10βˆ’28Β kgΒ msβˆ’110^{-28} \mathrm{~kg} \mathrm{~ms}^{-1}) is correct because the momentum of a photon is calculated using the formula p = h/Ξ», where h is Planck's constant and Ξ» is the wavelength.

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