NEET UG CHEMISTRY MCQ: SOLID STATE

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The edge of unit cell of fcc Xe crystal is 620 pm. The radius of Xe atom is

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Correct option: C

219.25\mathrm{ }pm

Option C (

219.25\mathrm{ }pm

) is correct because in an FCC lattice, the radius is related to the edge length by

r = \frac{{\sqrt{2}}}{{4}}a

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\mathrm{C}{\mathrm{s}^ + }

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