JEE MATHEMATICS MCQ: PERMUTATIONS

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The number of ways in which 3 children can distribute 10 tickets out of 15 consecutively numbered tickets themselves such that they get consecutive blocks of 5, 3 and 2 tickets is

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Correct option: C

{ }^8 {C}_5(3 !)^2

Option B (

\pi+1

) is correct because it maximizes the sum of the inverse trigonometric functions by considering the range of each function and the given domain.

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