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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
lim⁡x→∞{121−x3+31+x2+521−x3+71+x2+…}\lim \limits_{{x \rightarrow \infty}}\left\{\frac{1^2}{1-x^3}+\frac{3}{1+x^2}+\frac{5^2}{1-x^3}+\frac{7}{1+x^2}+\ldots\right\} equals
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Correct option: B
−103-\frac{10}{3}
Option B (-10/3) is correct because after simplifying the expression and taking the limit as x approaches infinity, the result is -10/3.

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