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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum 1(1!)+2(2!)+3(3!)+…+n(n!)1(1 !)+2(2 !)+3(3 !)+\ldots+n(n !) equals
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Correct option: C
(n+1)!−1(n+1) !-1
Option C ((n+1)!−1(n+1) !-1) is correct because by rewriting each term as ((k+1) - 1)k! and telescoping the sum, we arrive at (n+1)! - 1.

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