$\mathop \smallint \nolimits_2^3 \,\,\frac{{dx}}{{{x^2} - x}}$ is equal to

$\log \,\,\left( {\frac{2}{3}} \right)$

$\log \,\,\left( {\frac{1}{4}} \right)$

$\log \,\,\left( {\frac{8}{3}} \right)$

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \nolimits_2^3 \,\,\frac{{dx}}{{{x^2} - x}}

is equal to

View answer and explanation

Correct option: C

\log \,\,\left( {\frac{4}{3}} \right)

Option C is correct because the integral of 1/(x² - x) from 2 to 3 is solved using partial fraction decomposition, resulting in log(4/3).

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