JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Medium

1 of 1

Application +4 | -1

a, b

and

A

are given in

a

triangle and

c_1, c_2

are the possible values of the third side, then

c_1^2+c_2^2-2 c_1 c_2 \cos 2 A

is equal to

View answer and explanation

Correct option: C

4 a^2 \cos ^2 A

Option C (

4 a^2 \cos ^2 A

) is correct because by using the cosine rule and Vieta's formulas, the expression simplifies to

4 a^2 \cos ^2 A

More Questions from PROPERTIES OF TRIANGLES

Practice All Chapter MCQs →

{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s