$\mathop {\lim }\limits_{x \to 0} {\left( {\frac{{{e^x} + {e^{ - x}} - 2}}{{{x^2}}}} \right)^{1/{x^2}}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

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\lim\limits_{x \to 0} {\left( {\frac{{{e^x} + {e^{ - x}} - 2}}{{{x^2}}}} \right)^{1/{x^2}}}

is equal to

View answer and explanation

Correct option: D

{e^{1/12}}

The correct answer is D (

{e^{1/12}}

) because it is the result of evaluating the limit using series expansion and properties of exponential functions.

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