JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

k=\int_0^1 \frac{e^t}{1+t} d t

, then

\int_0^1 e^t \log _e(1+t) d t

is equal to

View answer and explanation

Correct option: C

e \ln 2-k

The correct answer is C (

e \ln 2-k

) because after applying integration by parts, the integral is expressed in terms of k, resulting in

e \ln 2 - k

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