JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

\left| x \right| < 1,\;

then the sum of the series

1 + 2x + 3{x^2} + 4{x^3} + ...\infty

will be

View answer and explanation

Correct option: D

\frac{1}{{{{\left( {1 - x} \right)}^2}}}

Option D (

\frac{1}{{{{\left( {1 - x} \right)}^2}}}

) is correct because the sum of the given infinite series can be found using the derivative of a geometric series.

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