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NEET UG CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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Analyzing +4 | -1
Identify the correct order of boiling points of the following compounds,

CH3(CH2)2CH2OH;CH3(CH2)2CHO;                          1                                                    2\begin{array}{l} \mathrm{C}{\mathrm{H}_3}{\left( {\mathrm{C}{\mathrm{H}_2}} \right)_2}\mathrm{C}{\mathrm{H}_2}\mathrm{OH};\mathrm{C}{\mathrm{H}_3}{\left( {\mathrm{C}{\mathrm{H}_2}} \right)_2}\mathrm{CHO};\\ \;\;\;\;\;\;\;\;\;\;\;\;\;1\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;2 \end{array}

CH3(CH2)2COOH:                          3\begin{array}{l} \mathrm{C}{\mathrm{H}_3}{\left( {\mathrm{C}{\mathrm{H}_2}} \right)_2}\mathrm{COOH}:\\ \;\;\;\;\;\;\;\;\;\;\;\;\;3 \end{array}
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Correct option: B
3 > 1 > 2
Option B (3 > 1 > 2) is correct because carboxylic acids have higher boiling points than alcohols, which have higher boiling points than aldehydes due to stronger intermolecular forces.

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