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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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The formula of sodium nitroprusside is:
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Correct option: B
Na2[Fe(CN)5NO]\mathrm{N}{\mathrm{a}_2}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_5}\mathrm{NO}} \right]
Option B (Na2[Fe(CN)5NO]\mathrm{N}{\mathrm{a}_2}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_5}\mathrm{NO}} \right]) is correct because the formula for sodium nitroprusside is Na2[Fe(CN)5NO]\mathrm{N}{\mathrm{a}_2}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_5}\mathrm{NO}} \right].

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