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JEE MATHEMATICS MCQ: PARABOLA

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Application +4 | -1

The equation of the parabola with

(-3,0)

as focus, and

x+5=0

as directrix, is

View answer and explanation

Correct option: C

y^2=4(x+4)

Option C (

y^2=4(x+4)

) is correct because it represents a parabola opening to the right with vertex at (-4, 0) and focus at (-3, 0).

More Questions from PARABOLA

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The equation of a common tangent to the parabolas

y=x^2

y=-(x-2)^2

P

moves such that slope of one tangent drawn from it to parabola

y^2=16 x

is four times the slope of other tangent, then the length of latus rectum of the conic represented by locus of

P

P,Q,R

be three points on parabola

{y^2} = 4x

P

R

Q

, then the locus of the mid-point of the chord

PR

is a parabola whose vertex is at The tangents at the end points of any chord through

(1,0)

to the parabola

y^2+4 x=8

intersect The focus of the parabola

x^2=-16 y

I

denotes the semi-latusrectum of the parabola

{y^2} = 4ax

SP

SQ

denote the segments of any focal chord

PQ,S

being the focus, then

SP,l

SQ

are in the relation