Skip to main content
Back to WORK-ENERGY-POWER

NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

1 Medium
1 of 1
Application +4 | -1
A man, by working a hand pump fixed to a well, pumps out 10β€…β€Šm310\mathrm{\;}{\mathrm{m}^3} water in 1 s. If the water in the well is 10 m below the ground level, then the work done by the man is (g=10msβˆ’2)\left( {\mathrm{g} = 10\mathrm{m}{\mathrm{s}^{ - 2}}} \right)
View answer and explanation
Correct option: D
106J{10^6}J
Option D (106J{10^6}J) is correct because it is calculated by multiplying the volume of water, density, gravity, and height.

More Questions from WORK-ENERGY-POWER

Practice All Chapter MCQs β†’
Type at least 2 characters or jump directly:
πŸ”“

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.