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JEE MATHEMATICS MCQ: COMBINATIONS

1 Easy
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Application +4 | -1
There are 5 points P1,P2,P3,P4,P5{P}_1, {P}_2, {P}_3, {P}_4, {P}_5 on the side AB{AB}, excluding AA and BB, of a triangle ABCA B C. Similarly there are 6 points P6,P7,…,P11{P}_6, {P}_7, \ldots, {P}_{11} on the side BC{BC} and 7 points P12,P13,…,P18{P}_{12}, {P}_{13}, \ldots, {P}_{18} on the side CA{CA} of the triangle. The number of triangles, that can be formed using the points P1,P2,…,P18{P}_1, {P}_2, \ldots, {P}_{18} as vertices, is:
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Correct option: B
751
Option B (751) is correct because it calculates the total number of possible triangles from 18 points, subtracting those formed only by points on the same side of the triangle.

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