JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Application +4 | -1

A point moves so that its distance from the point

(-1,0)

is always three times its distance from the point

(0,2)

. The locus of the point is

View answer and explanation

Correct option: B

A circle

Option B (A circle) is correct because the given condition leads to an equation of the form

8(x^{2}+y^{2})-36 y-2 x+35=0

, which is the general equation of a circle.

More Questions from 2D GEOMETRY SYSTEM

Practice All Chapter MCQs →

\alpha

(\alpha, 2 \alpha)

\Delta A B C

A(0,2), B(2,0)

C(4,4)

P

2 P A=3 P B

A

(0,0)

B

(4,-3)

(1, \sqrt{3}),(0,0)

(2,0)

(1,5),(-3,1) \,\&\,(-2,1)

9 x^2-16 y^2-18 x+32 y-23

=0

25 x^2+9 y^2-50 x-18 y+33=0

(0,0)(3,0)

(0,4)