$y=m x+c$ is a normal to the ellipse $x^2 / a^2+y^2 / b^2=1$ if $c^2$ is equal to

$\frac{\left(a^2-b^2\right)^2}{a^2 m^2+b^2}$

$\frac{\left(a^2-b^2\right)^2}{a^2 m^2}$

JEE MATHEMATICS MCQ: ELLIPSE

1 Medium

1 of 1

Application +4 | -1

y=m x+c

is a normal to the ellipse

x^2 / a^2+y^2 / b^2=1

c^2

is equal to

View answer and explanation

Correct option: C

\frac{\left(a^2-b^2\right)^2 m^2}{a^2+b^2 m^2}

Option D (

\frac{\left(a^2-b^2\right)^2 m^2}{a^2 m^2+b^2}

) is correct because it provides the correct condition for the line to be a normal to the ellipse.

Practice All Chapter MCQs →

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\mathrm{M}

\mathrm{mM}

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\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

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PSS',

A

A

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r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

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R

N P

Q

P

O