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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1

Let a be a factor of 120 . Then the number of positive integral solutions of

\mathrm{x}_1, \mathrm{x}_2, \mathrm{x}_3=\mathrm{a}

is

\mathrm{k}

then

\frac{\mathrm{k}}{80}

is

View answer and explanation

Correct option: A

4

Option A (4) is correct because the number of positive integral solutions of x1, x2, x3 = a is found to be 320, and then k/80 = 320/80 = 4.

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